The runs scored by two teams A and B on the first 60 balls in a cricket match are given below:
Represent the data of both the teams on the same graph by frequency polygons.
[Hint: First make the class intervals continuous.]
Solution:
The data given in the question is represented in discontinuous class interval. So, we have to make it in continuous class interval. The difference is 1, so taking half of 1, we subtract ½ = 0.5 = 0.5 from lower limit and add 0.5 to the upper limit. Then the table becomes:
| Number of balls | Class Mark | Team A | Team B |
| 0.5-6.5 | 3.5 | 2 | 5 |
| 6.5-12.5 | 9.5 | 1 | 6 |
| 12.5-18.5 | 15.5 | 8 | 2 |
| 18.5-24.5 | 21.5 | 9 | 10 |
| 24.5-30.5 | 27.5 | 4 | 5 |
| 30.5-36.5 | 33.5 | 5 | 6 |
| 36.5-42.5 | 39.5 | 6 | 3 |
| 42.5-48.5 | 45.5 | 10 | 4 |
| 48.5-54.5 | 51.5 | 6 | 8 |
| 54.5-60.5 | 57.5 | 2 | 10 |
The data of both the teams are represented on the graph below by frequency polygons.
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