(i) Draw a histogram to depict the given information.
(ii) Write the class interval in which the maximum number of surnames lie.
Solution:
(i) The width of the class intervals in the given data is varying.
We know that,
The area of rectangle is proportional to the frequencies in the histogram.
Thus, the proportion of the number of surnames per 2 letters interval can be calculated as given in the table below.
Number of letters | Number of surnames | Width of class | Length of rectangle |
1-4 | 6 | 3 | (6/3)×2 = 4 |
4-6 | 30 | 2 | (30/2)×2 = 30 |
6-8 | 44 | 2 | (44/2)×2 = 44 |
8-12 | 16 | 4 | (16/4)×2 = 8 |
12-20 | 4 | 8 | (4/8)×2 = 1 |
(ii) 6-8 is the class interval in which the maximum number of surnames lie.
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