Simplify: {Exercise 1.6 Page: 26 }

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(i) 22/3×21/5

Solution:

22/3×21/5 = 2(2/3)+(1/5) [⸪Since, am×an=am+n____ Laws of exponents]

= 213/15 [⸪2/3 + 1/5 = (2×5+3×1)/(3×5) = 13/15]


(ii) (1/33)7

Solution:

(1/33)= (3-3)7 [⸪Since,(am)= am x n____ Laws of exponents]

= 3-21


(iii) 111/2/111/4

Solution:

111/2/111/4 = 11(1/2)-(1/4)

= 111/4 [⸪(1/2) – (1/4) = (1×4-2×1)/(2×4) = 4-2)/8 = 2/8 = ¼ ]


(iv) 71/2×81/2

Solution:

71/2×81/2 = (7×8)1/2 [⸪Since, (am×b= (a×b)m ____ Laws of exponents]

= 561/2

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