Solution:
Let ABCD be a quadrilateral and P, Q, R and S are the mid points of AB, BC, CD and DA respectively.
Now,
In ΔACD,
R and S are the mid points of CD and DA respectively.
, SR || AC.
Similarly we can show that,
PQ || AC,
PS || BD and
QR || BD
, PQRS is parallelogram.
PR and QS are the diagonals of the parallelogram PQRS. So, they will bisect each other.
Hello,
May I help you ?