(i) x+y = 4
Solution:
To draw a graph of linear equations in two variables, let us find out the points to plot.
To find out the points, we have to find the values which x and y can have, satisfying the equation.
Here,
x+y = 4
Substituting the values for x,
When x = 0,
x+y = 4
0+y = 4
y = 4
When x = 4,
x+y = 4
4+y = 4
y = 4–4
y = 0
x | y |
0 | 4 |
4 | 0 |
The points to be plotted are (0, 4) and (4,0)
(ii) x–y = 2
Solution:
To draw a graph of linear equations in two variables, let us find out the points to plot.
To find out the points, we have to find the values which x and y can have, satisfying the equation.
Here,
x–y = 2
Substituting the values for x,
When x = 0,
x–y = 2
0 – y = 2
y = – 2
When x = 2,
x–y = 2
2–y = 2
– y = 2–2
–y = 0
y = 0
x | y |
0 | – 2 |
2 | 0 |
The points to be plotted are (0, – 2) and (2, 0)
(iii) y=3x
Solution:
To draw a graph of linear equations in two variables, let us find out the points to plot.
To find out the points, we have to find the values which x and y can have, satisfying the equation.
Here,
y = 3x
Substituting the values for x,
When x = 0,
y = 3x
y = 3×0
y = 0
When x = 1,
y = 3x
y = 3×1
y = 3
x | y |
0 | 0 |
1 | 3 |
The points to be plotted are (0, 0) and (1, 3)
(iv) 3 = 2x+y
Solution:
To draw a graph of linear equations in two variables, let us find out the points to plot.
To find out the points, we have to find the values which x and y can have, satisfying the equation.
Here,
3 = 2x+y
Substituting the values for x,
When x = 0,
3 = 2x+y
3 = 2×0+y
3 = 0+y
y = 3
When x = 1,
3= 2x+y
3 = 2×1+y
3 = 2+y
y = 3–2
y = 1
x | y |
0 | 3 |
1 | 1 |
The points to be plotted are (0, 3) and (1, 1)
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