Solution:
As the kite is in the shape of a square, its area will be
A = (½)×(diagonal)2
Area of the kite = (½)×32×32 = 512 cm2.
The area of shade I = Area of shade II
512/2 cm2 = 256 cm2
So, the total area of the paper that is required in each shade = 256 cm2
For the triangle section (III),
The sides are given as 6 cm, 6 cm and 8 cm
Now, the semi perimeter of this isosceles triangle = (6+6+8)/2 cm = 10 cm
By using Heron’s formula, the area of the III triangular piece will be
=
= √[10(10-6)(10-6)(10-8)] cm2
= √(10×4 ×4×2) cm2
= 8√5 cm2 = 17.92 cm2 (approx.)
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