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Class 8 | NCERT Solution Maths Chapter 4 | Practical Geometry | Exercise 4.1

 

Exercise 4.1 Page: 60

1. Construct the following quadrilaterals.

(i) Quadrilateral ABCD AB = 4.5 cm

BC = 5.5 cm

CD = 4 cm AD = 6 cm AC = 7 cm

Solution:

NCERT Solution For Class 8 Maths Chapter 4 Image 1The rough sketch of the quadrilateral ABCD can be drawn as follows.

(1) ∆ABC can be constructed by using the given measurements as follows.

NCERT Solution For Class 8 Maths Chapter 4 Image 2

(2) Vertex D is 6 cm away from vertex A. Therefore, while taking A as centre, draw an arc of radius 6 cm.

NCERT Solution For Class 8 Maths Chapter 4 Image 3

(3) Taking C as centre, draw an arc of radius 4 cm, cutting the previous arc at point D. Joint D to A and C.

NCERT Solution For Class 8 Maths Chapter 4 Image 4

ABCD is the required quadrilateral.

(ii) Quadrilateral JUMP JU = 3.5 cm

UM = 4 cm MP = 5 cm PJ = 4.5 cm PU = 6.5 cm

Solution:

The rough sketch of the quadrilateral JUMP can be drawn as follows.

NCERT Solution For Class 8 Maths Chapter 4 Image 5

(1) ∆ JUP can be constructed by using the given measurements as follows.

NCERT Solution For Class 8 Maths Chapter 4 Image 6

(2) Vertex M is 5 cm away from vertex P and 4 cm away from vertex U. Taking P and U as centres, draw arcs of radii 5 cm and 4 cm respectively. Let the point of intersection be M.

NCERT Solution For Class 8 Maths Chapter 4 Image 7

(3) Join M to P and U.

NCERT Solution For Class 8 Maths Chapter 4 Image 8

JUMP is the required quadrilateral.

(iii) Parallelogram MORE

OR = 6 cm

Solution:

RE = 4.5 cm

EO = 7.5

We know that opposite sides of a parallelogram are equal in length and also these are parallel to each other.

ie, ME = OR, MO = ER

NCERT Solution For Class 8 Maths Chapter 4 Image 9The rough sketch of the parallelogram MORE can be drawn as follows.

(1) ∆ EOR can be constructed by using the given measurements as follows.

NCERT Solution For Class 8 Maths Chapter 4 Image 10

(2) Vertex M is 4.5 cm away from vertex O and 6 cm away from vertex E. Therefore, while taking O and E as centres, draw arcs of 4.5 cm radius and 6 cm radius respectively. These will intersect each other at point M.

NCERT Solution For Class 8 Maths Chapter 4 Image 11

(3) Join M to O and E.

NCERT Solution For Class 8 Maths Chapter 4 Image 12

MORE is the required parallelogram.

(iv) Rhombus BEST

BE = 4.5 cm

ET = 6 cm

Solution:

We know that all sides of a rhombus are of the same measure. Hence, BE = ES = ST = TB The rough sketch of the rhombus BEST can be drawn as follows.

NCERT Solution For Class 8 Maths Chapter 4 Image 13

NCERT Solution For Class 8 Maths Chapter 4 Image 14(1) ∆ BET can be constructed by using the given measurements as follows.

(2) Vertex S is 4.5 cm away from vertex E and also from vertex T. Therefore, while taking E and T as centres, draw arcs of 4.5 cm radius, which will be intersecting each other at point S.

NCERT Solution For Class 8 Maths Chapter 4 Image15

(3) Join S to E and T.

NCERT Solution For Class 8 Maths Chapter 4 Image
NCERT Solution For Class 8 Maths Chapter 4 Image 16

BEST is the required rhombus.


Maths Class 8 NCERT Solutions Chapter 4 Exercises
NCERT Maths Solutions for Class 8 Exercise 4.1 – 1 Question (1 Long Answer)
NCERT Maths Solutions for Class 8 Exercise 4.2 – 1 Question (1 Long Answer)
NCERT Maths Solutions for Class 8 Exercise 4.3 – 1 Question (1 Long Answer)
NCERT Maths Solutions for Class 8 Exercise 4.4 – 1 Question (1 Long Answer)
NCERT Maths Solutions for Class 8 Exercise 4.5 – 4 Questions (4 Long Answers)