Solution:
Given,
AD is median of ΔABC. ∴, it will divide ΔABC into two triangles of equal area.
∴ar(ABD) = ar(ACD) — (i)
also,
ED is the median of ΔABC.
∴ar(EBD) = ar(ECD) — (ii)
Subtracting (ii) from (i),
ar(ABD) – ar(EBD) = ar(ACD) – ar(ECD)
⇒ar(ABE) = ar(ACE)
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